Monty Hall Problem

Monty Hall Problem ရဲ ့အစကို 21 ဆိုတဲ ့ Movie ၾကည့္ရင္းကေတြ ့ ျပီးစိတ္၀င္စားလို ့မ်ွ ေ၀လိုက္ပါတယ္..

Monty Hall Problem

ဒီဇာတ္လမ္းထဲမွ Professor ကေက်ာင္းသားေတြကို ေမးပါတယ္…

Game Show တစ္ခုမွာ..ျဖစ္ပါတယ္..

“He says that there are three doors – behind one is a car and behind the other two are goats. The contestant picks door A. At this point, the contestant has a 0.33 chance of winning a car (and a 0.66 chance of getting stuck with a goat). The host reveals that there is a goat behind door C. He then gives the contestant a chance to change his decision. Now, in the movie, they say that the contestant should switch to door B because there is a 0.66 chance that there is a car there (as opposed to the unchanged 0.33 chance in sticking with door A). I understand how they reached that conclusion, but I disagree with it. When the host reveals that there is a goat behind door C, wouldn’t that ‘extra’ 0.33 chance be divided between A and B equally rather than just all going to door B?”

ဒီျပသနာရဲ ့ မူလအစကေတာ့ အေမရိကန္ TV Game Show တစ္ခုျဖစ္တဲ့ “Let’s make a deal” က ျဖစ္ျပီး၊တင္ဆက္သူ Monty Hall ကို အစြဲျပဳျပီး၊ Monty Hall Problem လို ့ထင္ ရွားပါတယ္၊၊

ဒီျပသနာကို Parade Magzine က အခုလိုတင္ျပထားပါတယ္၊၊

Suppose you’re on a game show, and you’re given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what’s behind the doors, opens another door, say No. 3, which has a goat. He then says to you, “Do you want to pick door No. 2?” Is it to your advantage to switch your choice?
တယ္ကိုပဲအျငင္းပြားဖြယ္ရာေကာင္းေသာ၊ စိတ္၀င္စားဖြယ္ေကာင္းေသာ ရွင္းလင္းတင္ျပခ်က္မ်ား၊ယူဆခ်က္မ်ားျဖစ္တဲ့အတြက္၊ စိတ္၀င္စားသူမ်ား ေအာက္ပါ web link မ်ားမွာ ဆက္လက္ေလ့လာစူးစမ္းႏိုင္ၾကပါတယ္၊၊

http://en.wikipedia.org/wiki/Monty_Hall_problem

http://www.montyhallproblem.com

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